I've read about the difference between double precision and single precision. However, in most cases, float and double seem to be interchangeable, i.e. using one or the other does not seem to affec...
494 A Double is not an Integer, so the cast won't work. Note the difference between the Double class and the double primitive. Also note that a Double is a Number, so it has the method intValue, which you can use to get the value as a primitive int.
From what I have read, a value of data type double has an approximate precision of 15 decimal places. However, when I use a number whose decimal representation repeats, such as 1.0/7.0, I find tha...
L Specifies that a following a, A, e, E, f, F, g, or G conversion specifier applies to a long double argument. The same rules specified for fprintf apply for printf, sprintf and similar functions.
A Double in Java is the class version of the double basic type - you can use doubles but, if you want to do something with them that requires them to be an object (such as put them in a collection), you'll need to box them up in a Double object.
Possible Duplicate: Java : different double and Double in comparison In a sample java program for one of my labs, I have two different methods taking Double and double parameters respectively. ...
In my earlier question I was printing a double using cout that got rounded when I wasn't expecting it. How can I make cout print a double using full precision?
A double which is usually implemented with IEEE 754 will be accurate to between 15 and 17 decimal digits. Anything past that can't be trusted, even if you can make the compiler display it.
double d = ((double) num) / denom; But is there another way to get the correct double result? I don't like casting primitives, who knows what may happen.
I have a double value. I want to format this value in the format of x.yz. How do I do this? I keep getting digits truncated. Can someone tell me how to do this in C#? Thanks!
